Raised by:
Alistair Miles
Opened on:
This is a sub-issue of ISSUE-44.

Currently, skos:broader is *not* defined as an irreflexive property.

Therefore, graphs such as:

<A> skos:broader <A> .

... are consistent with the SKOS data model.

However, such a graph would never be found in a representation of a thesaurus 
or classification scheme, and if it did, would probably indicate some sort of 

If skos:broader were formally defined as an irreflexive property in the 
normative specification, this would endorse stronger checking of instance data 
against the SKOS data model, which would probably be both useful and 
appropriate to most SKOS use cases.

Should skos:broader be normatively irreflexive?
Related emails:
  1. ISSUE-69: BroaderIrreflexive (from on 2008-01-16)
  2. Re: ISSUE-69: BroaderIrreflexive (from on 2008-01-16)
  3. Re: ISSUE-69: BroaderIrreflexive (from on 2008-01-23)
  4. Comment: ISSUE-69 (from on 2008-02-10)
  5. [SKOS] Issues Review [From Alistair] (from on 2008-02-17)
  6. [Fwd: [SKOS] Issues Review (from on 2008-02-21)
  7. [SKOS] Issues Review (from on 2008-02-21)
  8. [SKOS] Issue owners - preparation for Washington (from on 2008-04-15)
  9. Re: [SKOS] Issue owners - preparation for Washington (from on 2008-04-21)
  10. SKOS Reference Review Response (from on 2008-08-22)
  11. RE: SKOS Reference Review Response (from on 2008-08-25)
  12. RE: SKOS Reference Review Response (from on 2008-08-26)

Related notes:

2008-05-07: RESOLUTION: to resolve skos:related, skos:broader and skos:broaderTransitive are not normatively irreflexive