29314 2015-11-29 18:30:41 +0000 [FO31] Code example in http://www.w3.org/TR/xpath-functions-31/#func-random-number-generator does not work 2016-03-22 09:55:09 +0000 1 1 1 Unclassified XPath / XQuery / XSLT Functions and Operators 3.1 Candidate Recommendation PC Windows NT CLOSED FIXED P2 editorial --- 1 martin.honnen mike andrew_coleman public-qt-comments oldest_to_newest 124313 0 martin.honnen 2015-11-29 18:30:41 +0000 I have tried the code example given in http://www.w3.org/TR/xpath-functions-31/#func-random-number-generator, it has the code declare %public function r:random-sequence($length as xs:integer) as xs:double* { r:random-sequence($length, fn:random-number-generator()) }; declare %private function r:random-sequence($length as xs:integer, $G as map(xs:string, item())) { if ($length eq 0) then () else ($G?number, r:random-sequence($length - 1, $G?next()) }; The is a closing `)` missing in the `else` clause, should be declare %public function r:random-sequence($length as xs:integer) as xs:double* { r:random-sequence($length, fn:random-number-generator()) }; declare %private function r:random-sequence($length as xs:integer, $G as map(xs:string, item())) { if ($length eq 0) then () else ($G?number, r:random-sequence($length - 1, $G?next())) }; 124628 1 mike 2016-01-19 14:43:52 +0000 Thank you, this has now been fixed.