24383 2014-01-24 16:02:10 +0000 Is :nth-match() and :nth-last-match() are necessary? 2014-01-28 15:13:12 +0000 1 1 1 Unclassified CSS Selectors unspecified PC Windows NT NEW P2 normal --- 1 crimsteam fantasai.bugs public-css-bugzilla oldest_to_newest 99007 0 crimsteam 2014-01-24 16:02:10 +0000 It's clear how this selector "p.foo:nth-child(even)" work, like you describe, and why you put this ":nth-match(even p.foo)". But this two selectors: :nth-match(even of p.foo) p.foo:nth-of-type(even) don't have the same result? So only improve for this new pseudo is that whe can use selector list: :nth-match(even of p,div) {} the same as: :nth-match(even of p), :nth-match(even of div) {} p:nth-of-type(even), div.foo:nth-of-type(even) {} or :nth-match(even of p,div) means, take p and div (it would be one sub sibling list) and start indexing. This will be nice, but when I see that selector list is treated as union, benefit is less. Or add new variant (conjunction) for argument in functional pseudo, like p^div, p&div, or sth similar. 99299 1 crimsteam 2014-01-28 15:13:12 +0000 Ok, now I see that :nth-match(even of p.foo) p.foo:nth-of-type(even) is not same, this is same: :nth-match(even of p) p:nth-of-type(even) But still wondering how interpretate list of selector in this :nth-match(even of p,div).