15539 2012-01-12 22:23:53 +0000 [QT3] alternate result for group-010 2012-01-12 22:26:21 +0000 1 1 1 Unclassified XPath / XQuery / XSLT XQuery 3 & XPath 3 Test Suite Last Call drafts PC Windows XP CLOSED FIXED P2 normal --- 1 andrew.eisenberg benjie.nguyen mike public-qt-comments oldest_to_newest 62620 0 andrew.eisenberg 2012-01-12 22:23:53 +0000 The query in group-010 is: for $x in //employee let $key := if ($x/@gender='male') then number('NaN') else 42 group by $key order by $key return <group key="{$key}" count="{count($x)}"/> I believe that two results should be accepted, one with the NaN group before the non-NaN group, and one with the non-NaN group before the NaN group. The order by by clause is a no-op here, because an implementation may chose either empty-least or empty-greatest for the default order for empty sequences. This choice determines whether the NaN group appears first or last. 62621 1 andrew.eisenberg 2012-01-12 22:26:11 +0000 I have removed the order by clause from the query and allowed the two results that I described.