Simple SPARQL Example
SELECT ?cat ?val
WHERE (?x rdf:value ?val) (?x category ?cat)
- Returns:
-
[["Total Members",100],["Total Members",200],…,["Full Members",10],…] -
[["Total Members",100],["Total Members",200],…, -
["Full Members",10],…] - Note the role of
?x: it helps defining the pattern, but is not returned
